Câu hỏi của Công Chúa Họ Kim - Toán lớp 6 - Học toán với OnlineMath

a, Ư(12)=\(\left\{\pm1;\pm2;\pm3;\pm4\pm6\pm12\right\}\)

Ư(18)=\(\left\{\pm1;\pm2;\pm3;\pm6;\pm9;\pm18\right\}\)

ƯC(12;18)=\(\left\{\pm1;\pm2;\pm3;\pm6\right\}\)

c,ƯC(45;20;72)=\(\left\{\pm1\right\}\)

Câu hỏi của Công Chúa Họ Kim - Toán lớp 6 - Học toán với OnlineMath

a) Ư (12) = {1;2;3;4;6;12}

Ư (16) = {1;2;4;8;16}

Ư (24) = {1;2;3;4;6;8;12;24}

ƯC (12; 16; 24) = {1;2;4}

b) ƯC (5; 15; 35) = {1;5}

c) BC (8; 12; 24) = {0;24;48}

d) BC (5; 15; 35) = {0;105;210;…}

a) Ư(8) = {1;2;4;8}; Ư(12) = {1;2;3;4;6;12} => ƯC(8;12) = {1;2;4;}

b) Ư(24) = {1;2;3;4;6;8;12;24}; Ư(32) = {1;2;4;8;16;32} => ƯC(24; 32) = {1;2;4;8;}

c) Ư(7) = {1;7} ; Ư(10) = {1;2;5;10} => ƯC(7;10) = {1}

d) 8 = 2³; 10 = 2.5 => BCNN (8;10) = 2³.5 = 40 => BC(8;10) = B(40) = {0;40;80;...}

e) 25 = 5² => BCNN(2;3;25) = 2.3.5² = 150 => BC (2;3;25) = B(150) = {0;150; 300; ...}

2) N = {0;1;2;3;...}; N* = {1;2;3;....} => N giao N* = {1;2;3;...} = N*

a) Ư(8) = {1;2;4;8}; Ư(12) = {1;2;3;4;6;12} => ƯC(8;12) = {1;2;4;}

Vâu b,c,d,e tương tự nha bn

2) N = {0;1;2;3;...}; N* = {1;2;3;....} => N giao N* = {1;2;3;...} = N*

hok tốt

a) 

\(Ư\left(12\right)=\left\{1;2;3;4;6;12\right\}\)

\(Ư\left(18\right)=\left\{1;2;3;6;9;18\right\}\)

=> \(ƯC\left(12;18\right)=\left\{1;2;3;6;\right\}\)

b) \(B\left(15\right)=\left\{0;15;30;45;60;90;105...\right\}\)

   \(B\left(21\right)=\left\{0;21;42;63;84;105;...\right\}\)

=> \(BC\left(15;21\right)=\left\{0;105;...\right\}\)

 c)

 \(20=2^2.5\)

\(24=2^3.3\)

\(28=2^2.7\)

=> \(BCNN\left(20;24;28\right)=2^3.3.5.7=840\)

=> \(BC\left(20;24;28\right)=B\left(840\right)=\left\{0;840;1680;...\right\}\)